Calculate `DeltaG` for
(i) `H_(2)O(l,2 atm , 300 K) to H_(2)O(g, 2 atm , 300 K ) `
(ii) `H_(2)O(l,P" "atm , 300 K) to H_(2)O(g, P" "atm , 300 K )` Cacluate p for which `DeltaG = 0`
Given: `DeltaH_(373)= 40 kJ`
`" "C_(P) (H_(2) O, l) = 75 J//mol //K`
`" "C_(P) (H_(2) O, g) = 35 J//mol //K`


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Correct Answer - (i) `DeltaG= V (P_(2)- P_(1)) + [DeltaH_(300) - 300 DeltaS_(300)]+ nRT ln .(P_(2))/(P_(1))`
(ii) P = 26.28 atm

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