Aniline on heating with conc. `HNO_(3)+` conc. `H_(2)SO_(4)` mixture yields
A. `o-`and p-Nitoanilines
B. `m-`Nitroaniline
C. A black tarry matter
D. No reaction
Correct Answer - C
Since `HNO_(3)` is also a strong oxidising agent, therefore, aniline forms tarry oxidation products along with some oxidation products.
Correct Answer - A
`HNO_(3)` acts as a base as it provides p-nitrophenol.
`HNO_(3) Leftrightarrow H^(+)+HSO_(4)`
`O_(2)N-OH+H^(+) to NO_(2)^(+)+H_(2)O`
Correct Answer - D
Direct treatement of aniline `(1^(@)" Amine")` without protecting `-NH_(2)` group with conc. `HNO_(3)` redults in the black tarry mixture of many oxidation products.
Correct Answer - D
Yields of three isomeric nitroanilines are in the order
`p(51%) gt m (47%) gt o (2%)`
Large yields of m-nitroaniline is due to the fact that aniline...
Dilute `H_(2)SO_(4)` behaves as a proton acid and zinc metal displaces hydrogen from the acid.
`Zn+H_(2)SO_(4)("dil")to ZnSO_(4)+H_(2)`
Concentrated `H_(2)O_(4)` behaves as a strong oxidising agent and itself is reduced to...
Correct Answer - 15.44 M
`"Mass of solution"= 100 g, "Mass os "HNO_(3)=69 g`
`"Volume of solution"=(100 g)//(1.41" g cm"^(-3))=70.92 cm^(3)=0.07092 dm^(3)`
`"Molar mass of "HNO_(3)=1 +14 +3xx16=63" g mol"^(-1)`
`"Molarity...