a) write dimensions of first order reaction.
b) Give reason for no change in concentration of `H_(2)` and `Cl_(2)` with respect to time in the reactions.
`H_(2)(g) + Cl_(2) overset(hv)to 2HCl(g)`
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The reaction takes place in two steps as `(i) NO_(2) Cl _((g)) overset(K_(1)) to NO_(2(g)) +Cl_((g))` `(ii ) NO_(2) Cl_((g)) +Cl_((g)) overset(K_(2))
Correct Answer - D Common in continuous reaction is chlorine
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The form of rate law for a reaction is expressed as, rate = k`[Cl_(2)][NO]^(2)` Find out the order of the reaction with respect to `Cl_(2)`, with resp
The Rate Law equation for the reaction is (r ) = `k[Cl_(2)][NO]^(2)` Order w.r. to `Cl_(2)` = 1, Order w.r. to NO=2 Overall order of the reaction = 1+2=3`
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The rate of reaction, 2NO + `Cl_(2) to 2NOCl` is doubled when concentration of `Cl_(2)` is doubled and becomes eight times when concentration of both
Rate( r) = `k[NO]^(x)[Cl_(2)]^(y)` ………….(i) Rate (2r) = `k[NO]^(x)[2Cl_(2)]^(y)`……………(ii) Rate (8r) = `k[2NO]^(x)[2Cl_(2)]^(y)`……………….(iii) Divide eqn. (iii) by eqn. (ii), `(8r)/(2r) = k[2NO]^(x)[2Cl_(2)]^(y)` or `4=[2]^(x)` or `[2]^(x)` or x=2 Divide eqn....
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A reaction `SO_(2)Cl_(2) to SO_(2)+ Cl_(2)` is first order reaction with half life period `3.15 xx 10^(4)`s at `320^(@)`C. What percentage of `SO_(2)C
`k=0.693/t_(1//2)=0.693/(3.15 xx 10^(4)s)= 2.2 xx 10^(-5)s^(-1)` For the first order reaction, `t=2.303/k log a/(a-x)` `k=2.2 xx 10^(-5)s^(-1)`, t=90 min `=90 xx 60=5400s` `(5400s) = 2.303/(2.2 xx 10^(-5)s^(-1)) log a/(a-x)` (5400s)...
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A substance reacts with initial concentration of a mol `dm^(-3)` accroding to zero order kinetics. The time it takes for the completion of the reactio
Correct Answer - C c) For zero order reaction `k=1/t{[A]_(0)-[A]}` When the reaction is complete, [A]=0 `therefore k=([A]_(0))/t=a/t` or `t=a/k`
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In a first order reaction, the concentration of the reactant decreases from 0.6 M to 0.3 M in 30 minutes. The time taken for the concentration to chan
Correct Answer - D d) 0.1 M `overset(t_(1//2))to 0.05M overset(t_(1//2))to0.025` Time taken `=2 xx t_(1/2) = 2 xx 30 =60` min
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A reaction was found to be of second order with respect to concentration of carbon monoxide. If the concentration of carbon monoxide is doubled with e
Correct Answer - C c) rate = `k[CO]^(2)` By doubling the concentration of carbon monoxide (CO),the rate of reaction will become four times.
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The rate of reaction `2NO + Cl_(2) to 2NOCl` is doubled when the concentration of `Cl_(2)` is doubled and becomes eight times when the concentration o
Rate ( r) = `k[NO]^(x)[Cl_(2)]^(y)`…………..(i) Rate (2r)`= k[NO]^(x)[2Cl_(2)]^(y)`………..(ii) Rate (8r) = `k[2NO]^(x)[2Cl_(2)]^(y)`…………(iii) `(8r)/(2r) = (k[2NO]^(x)[2Cl_(2)]^(y))/(k[NO]^(x)[2Cl_(2)]^(y))` `4= [2]^(x) or x=2` `(2r)/(r)=(k[NO]^(x)[2Cl_(2)]^(y))/(k[NO]^(x)[Cl_(2)]^(y))` `2= [2]^(y)` or y=1 Order of reaction= 2+1=3.
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A reaction with respect to X is zero order till the concentration is reduced to half of initial concentration.Then this reaction become first order wi
Correct Answer - B `xto` product (zero order) Till the concentration of X changes from `X_0` to `X_0/2` , it is zero order with rate constant k. Time taken for concentration...
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Calculate the standard potential for the reaction, `Hg_(2)Cl_(2)+Cl_(2) rarr 2Hg^(2+)+4Cl^(-)` Given : `{:(Hg_(2)Cl_(2)+2e^(-) rarr 2Hg+2Cl^(-),,E^(@)
Correct Answer - `-0.08` volt First determine `E^(@)` for `Hg_(2)Cl_(2) rarr 2Hg^(2+) +2Cl^(-) +2e^(-)` electrode. It comes to -1.44 volt. This electrode is now coupled with `Cl_(2)+2e^(-) rarr 2Cl^(-)` electrode.
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