For a reaction carried at 400 K, `NO_(2)(g) + CO_(2)(g) to CO_(2)(g) + NO_(2)(g)`, the proposed mechanism is as follows: `NO_(2) + NO_(2) overset("Slo

Question

For a reaction carried at 400 K, `NO_(2)(g) + CO_(2)(g) to CO_(2)(g) + NO_(2)(g)`, the proposed mechanism is as follows: `NO_(2) + NO_(2) overset("Slo

For a reaction carried at 400 K,
`NO_(2)(g) + CO_(2)(g) to CO_(2)(g) + NO_(2)(g)`, the proposed mechanism is as follows:
`NO_(2) + NO_(2) overset("Slow")to NO + NO_(3) NO_(3) + CO overset("Fast")to CO_(2) + NO_(2)`
What is the rate law for the reaction?

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Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

The slow step for the reaction is:
`NO_(2) + NO_(2) to NO + NO_(3)` (Slow)
The rate law equation is:
`Rate( r) = k[NO_(2)][NO_(2)]= k[NO_(2)]^(2)`.

For a reaction carried at 400 K, `NO_(2)(g) + CO_(2)(g) to CO_(2)(g) + NO_(2)(g)`, the proposed mechanism is as follows: `NO_(2) + NO_(2) overset("Slo

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