Corrosion of iron is essentially an electrochemical phenomenon where the cell reactions are
A. Fe is oxidised to `Fe^(2+)` and dissolved oxygen in water is reduced to `OH^(-)`
B. (b) Fe is oxidised to `Fe^(3+)` and `H_(2)O` is reduced to `O_(2)^(2-)`
C. Fe is oxidised to `Fe^(2+)` and `H_(2)O` is reduced to `O_(2)^(-)`
D. Fe is oxidised to `Fe^(2+)` and `H_(2)O` is reduced to `O_(2)`


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Correct Answer - A
(a) Al anode : `Fe to Fe^(2+)+2e^(-)xx2`.
`("Al cathode" : O_(2)+2H_(2)O+4e^(-) to 4OH^(-))/("Overall reaction" , 2Fe+O_(2)+2H_(2)O to 2Fe(OH)_(2))`
`:.` It is the correct option.

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