The probability that the drawn card from a pack of 52 cards is neither an ace nor a spade is
(a) 9/13
(b) 35/52
(c) 10/13
(d) 19/26
Correct option is: D) \(\frac 3{25}\) Total number of outcomes = 50. Number which is divisible by 8 from 1 to 50 are (8, 16, 24, 32, 40, 48) \(\therefore\) Favourable outcomes = 6. \(\therefore\) Required probability = \(\frac...
2 Answers 1 viewsCorrect option is: A) \(\frac{1}{5}\)
2 Answers 1 viewsCorrect option is: C)\(\frac 3{25}\) Total No which are divisible by 8 from 1 to 50 is 6. \(\therefore\) Probability that drawn card is divisible by 8 = \(\frac 6{50}\) = \(\frac 3{25}\)
2 Answers 1 viewsi. B) \(\frac{3}{26}\) ii. D) \(\frac{4}{3}\) iii. C) \(\frac{7}{13}\)
2 Answers 1 viewsHere, S={(1,2),(2,1),(1,3),(3,1),(2,3),(3,2),(1,4),(4,1),(1,5),(5,1),(2,4),(4,2),(2,5),(5,2),(3,4),(4,3),(3,5),(5,3),(5,4),(4,5)} `rArrn(S)=20` Let random variable variable be X which denotes the sum of the numbers on two cards drawn. X=3,4,5,6,7,8,9 At X=3,P(X)=`2/20=1/10` At X=4,P(X)`=2/10=1/10` At X =5,P(X)=`4/20=1/5` At X=6,...
2 Answers 1 viewsRequired probability=`4/52cdot4/52=1/13xx1/13`
2 Answers 1 viewsCorrect Answer - `({26!}^(4))/({13!}^(4)xx52!)` We have to find the probability that out of 26 cards drawn at random from the pack of cards, 13 will be red and 13 black. The...
2 Answers 1 viewsCorrect Answer - C If A draws card higher than B, then the number of favorable cases is (n - 1) + (n + 2) + … + 3 + 2...
2 Answers 1 views