An atom emits energy equal to `4 xx 10^(-12)` erg. In which part of the electromagnetic spectrum does the corresponding line lie?
A. UV region
B. Infrared region
C. Visible region
D. Microwave region.


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Correct Answer - C
The wavelength corresponding to energy `4xx10^(-12)` ergs is
`lambda=(hC)/(DeltaE)=(6.62xx10^(-34)xx3xx10^8)/(4xx10^(-12)xx10^(-7))`
`=4.965xx10^(-7)`m=4965 Ã…
Visible region extends from 3800 Ã…-7600 Ã…

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