Other factors being constant which bond order is expected to correspond to shortest bond length

Correct Answer - B `lamda/2 = 20 therefore lamda = 40cm` `lamda = l=40cm`

Correct Answer - A 0.5 m `BaCl_(2)` will react with 0.5 M `H_(2)SO_(4)` `BaCl_(2)+H_(2)SO_(4) rarr BaSO_(4)+2HCl` Here `BaCl_(2)` is a limiting reactant `:. BaSO_(4)` produced `=0.5 M`.

Correct Answer - B Reducing power increases in the order HF lt HCl lt HBr lt HI

Correct Answer - D As total no. of electron pairs are four [3S.A + 1 L.P],`therefore` it exhibits `sp^3` hybrid state, but due to the presence of one lone pair electrons...

Correct Answer - D `N-= N` bond length among the given species is shortest.

Correct Answer - D Ethyl (alkyl) group is electron repelling group.

(a) Bi (b) N (c )Bi (d) N.

Correct Answer - A Please note that greater the magnitude of negative charge on the carbonyl complex easier will be for the metal atom to make available its electrons to participate...

Correct Answer - A-r; B-s ; C-q; D-p Zero order x=kt First order `K=1/t"In"a/(a-x)` Second order `K=1/t[1/(a-x)-1/a]` Third order `K=1/(2t)[1/(a-x)^2-1/a^2]`

Correct Answer - B (a)`N_2=sigma1s^2 sigma^**1s^2 sigma2s^2 sigma^**2s^2 pi2p_x^2 =pi2p_y^2 sigma2p_z^2` B.O.`=(10-4)/2=3` , n=0(D) `N_2^(+)=sigma1s^2 sigma^(**)1s^2 sigma2s^2 sigma^** 2s^2 sigma^** 2s^2 pi2p_x^2 = pi 2p_y^2 sigma2p_z^1` B.O.=`(9-4)/2=2.5` , n=1(P) (b)`O_2^+=sigma1s^2 sigma^**1s^2...