The correct order of increasing bond angles in the following triatomic species is
A. `NO_(2)^(+) lt NO_(2) lt NO_(2)^(-)`
B. `NO_(2)^(+) lt NO_(2)^(-)lt NO_(2)`
C. `NO_(2)^(-) lt NO_(2)^(+) lt NO_(2)`
D. `NO_(2)^(-) lt NO lt NO_(2)^(+)`


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Correct Answer - D
N on `NO_(2)^(+)` is sp-hybridized , therefore, its bond angle is `180^(@)`. Both NO and `NO_(2)^(-)`, on the other hand, are `sp^(2)`-hybrisized. In `NO_(2)^(-)`, there is one unshared electron on N while in `NO_(2)^(-)` there is one unshared electrons pair on N atoms.
Hence, in `NO_(2),bp-bp` repulsions are stronger than lp-lp repulsions, and hence the bond angle increases from 120 to `130^(@)`. however in `NO_(2)^(-)`, the lp-lp repulsions are stronger than lp-lp repulsion and hence. the angle decreases from `120^(@)` to `115^(@)` (D) is correct.

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