The first ionisation in electron volts of nitrogen and oxygen atoms are, respectively , given by
A. 14.5,13.5
B. 13.6, 14.6
C. 13.6, 13.6
D. 14.6, 14.6
Correct Answer - A
N atom has exactly half-filled p-orbitals. Since extra stability is associated with exactly half- filled orbitals, therefore, nitrogen has slightly higher ionization energy than oxygen.
Correct Answer - B
Amount of nitrogen gas at 5 atm
`=5xx5.5=27.5mg`
`=27.5xx10^(-3)g`
`"Mole fraction of "N_(2)=("Moles of "N_(2))/("Moles of "H_(2)O+"Moles of "N_(2))`
`("Moles of "N_(2))/("Moles of "H_(2)O)" "(becauseN_(2)lt ltH_(2)O)`
`=((27.5xx10^(-3))/(28))/(180/(18))=1xx10^(-5)`
Correct Answer - B
`alpha =1.34 %=(1.34)/(100)=1.34 xx 10^(-2)`
`C=0.1 mol L^(-1)`
`K_(a)=C alpha^(2) =0.1 xx (1.34 xx 10^(-2))^(2)`
`=1.7956 xx 10^(-5)`
Correct Answer - C
In first oxidie,
Mass of `2*24` L of nitrogen at STP `=2*8g`
`:.` Mass of oxygen `=4*4-2*8=1*6g`
In second oxide
Mass of `22*4`L of nitrogen at STP...
Correct Answer - B
Mass of 2 molecular of caffine = 194 amu
N present in one molecule `= (28.9xx194)/(100)`
= 56 amu
56 amu pertains to 4 nitrogen (N) atoms
Correct Answer - D
Amount of nitrogen present in one mole of akaloid i.e., in 162 g `= (162xx17.28)/(100)`
`:.` No. of nitrogen atoms per molecule
`=(162xx17.28)/(100x24)=2`(approx.)
Correct Answer - C
First find the number of moles of three elements
No. of moles of `Na=(2.04g)/(23gmol^(-1))=0.0887` mol
Number of moles of C
`=(2.65xx10^(27)"atoms")/(6.02xx10^(23)"atoms"mol^(-1))=0.0440 mol`
Number of moles of `O=0.132...