In the combustion of 5.00 g of a metal, 9.44 g of metal oxide are formed. Hence, equivalent mass of the metal is
A. `4.44` g
B. `9.00` g
C. `5.00` g
D. `2.22` g
Correct Answer - B
Matel `= 5. 00` g
Metal oxide ` = 9. 44` g
Oxygen combined `= 4. 44` g
`4.44` g of oxyen combined with `= 5. 00` g metal
`therefore 8 ` g oxygen combined with `= 5.00/4.44 xx 8` g metal
`=9.00` g
Correct Answer - C
`CH_(4)+2O_(2)toCO_(2)+2H_(2)O,=-400KJ//mol`
`because` for 2mole or 36 gm water, heat released `=-400KJ//mol`
`:.` for gm water, heat released will be
`=(-400)/(36)xx40`
`-444.44 KJ`
Correct Answer - C
Equivalent mass of metal =12
Equivalent mass of oxygen = 8 g `"mol"^(-1)`
`therefore` Equivalent mass of metal oxide = 20 g `"mol"^(-1)`
Correct Answer - A
Equivalent mass lof `Cl = 35.5` g
Equivalent mass of copper chloride ` = 99.0 ` g
Equivalent of copper combined `=99. 0 - 35. 5 =...
Correct Answer - B
Equivalents of metal=Equivalents of metal sulphate
`("wt.of metal")/("Eq. wt. of metal")("wt. of metal sulphate")/("Eq. wt. metal sulphate")`
`(2)/(x)=(6.8)/(x +48)`
`6.8x=2x+96`
`4.8x=96`
`x=(96)/(4.8)=20`
Correct Answer - B
Suppose no. of `O^(2-)` ions = n
`:.` No .of octahedral voids = n
Metal ions (M) occupying octahedral voids `=(2)/(3)n`
`:.` Ratio of M : `O^(2-)=(2)/(3)n:n=(2)/(3):1=2:3`...