State impulse – momentum theorem? A ball of mass 0.1kg is thrown against a wall. It strikes the wall normally with a velocity

(b) Er= Eoi cos(kz+ωt).

(c) –(0.9i + 1.2j)

If F is the force of the finger on the book, F = N, the normal reaction of the wall on the book. The minimum upward frictional force needed to...

The recoil velocity of the gun, 0.4 m s–1

Both are free falling. Hence, there is no acceleration of one w.r.t. another. Therefore, relative speed remains constant (=40 m/s ).

Mass of canon ball = 500g = 0.5 kg Speed, v = 15m/s (a) Kinetic energy of ball = 1/2 × mass x (velocity)2  = 1/2 ×0.5 ×(15)2  = 1/2 ×0.5 ×225=56.25J (b) Momentum of...

Potential energy of the ball at the highest point is mgh. Hint: At the highest point, the ball momentarily comes to rest and thus its kinetic energy becomes zero.

Potential energy at the maximum height= initial kinetic energy = 1/2 mv2 = 1/2×0.20 ×20 ×20=40J

(a) Potential energy at the greatest height = initial kinetic energy or, mgh = 1/2 mv2  = 1/2 ×0.500 ×15 ×15=56.25J (b) Kinetic energy on reaching the ground= potential energy at the greatest...

On heating, the ball expands and increases in size and cannot pass the ring when left on it. As the ball cools, it contracts, size becomes less than a ring...