Had Ajita scored 10 more marks in her mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks.How many marks did she get in the test?


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Solution : Let her actual marks be x

Therefore, 9 (x +10) = x2

i.e., x2 – 9x – 90 = 0

i.e., x2 – 15x + 6x – 90 = 0

i.e., x(x – 15) + 6(x –15) = 0

i.e., (x + 6) (x –15) = 0

Therefore, x = – 6 or x =15

Since x is the marks obtained, x ≠ – 6. Therefore, x = 15.

So, Ajita got 15 marks in her mathematics test.

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Let her actual marks be x 

Therefore, 9 (x +10) = x2 

i.e., x2 – 9x – 90 = 0 

i.e., x2 – 15x + 6x – 90 = 0 

i.e., x(x – 15) + 6(x –15) = 0 

i.e., (x + 6) (x –15) = 0 

Therefore, x = – 6 or x = 15 

Since x is the marks obtained, x ≠ – 6. Therefore, x = 15. 

So, Ajita got 15 marks in her mathematics test.

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