The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4 2/15 cm. What is the length of either of the remaining equal sides?
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Let the length of equal sides be x cm.
Perimeter = x cm + x cm + Base = 4 2/15 cm
2x + 4/3 = 62/15
On transposing 4/3 to R.H.S, we obtain
2x = 62/15 - 4/3
2x = 62 - 4 x 5/15 = 62 - 20/15
2x = 42/15
On dividing both sides by 2, we obtain
2x/2 = 42/15 x1/2
x = 7/5 = 1 2/5
Therefore, the length of equal sides is 1 2/5 c m.