There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
(A.)Rs. 2160 (B.)Rs. 3120 (C.)Rs. 3972 (D.)Rs. 6240
Answered Feb 05, 2023
Solution: Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R=100*60/100*6 =10% p.a
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
C.I=Rs.[12000*[1+10/100]3−1] =Rs.3972
(b) Simple interest = P*R*T/100 = Rs 3921
(e) Amount = Principal ( 1 + Rate / 100 ) Time = 5000 ( 1 + 8 / 100) 2 = 5000 ( 1 + 2 / 25 ) 2 = 5000 x 27/25 x...
(b) Simple Interest = P×R×T / 100 = 31400 x 8 x 12 / 100 = Rs 30144 Therefor Required amount = Rs (31400 + 30144) = Rs 61544
(a) Required Simple Interest = 5760 x 3 x 6 / 100 = Rs 1036.80
(d) Amount invested = 8376x100 / 8x6 = Rs 17450
(e) Simple interest = principal x time x rate /100 = 16500 x 4 x 16 / 100 = Rs 10560
The correct option is (C) (x – 5) years.
Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 years Simple Interest = (P*R*T)/100 Rs280 = 56000×x×2/100 Rs280 = 560×2x 280/ 560 = 2x 1/2 = 2x 1/2×2=x 1/4 =...
(a) Principal (P) = Rs 10, 800 Rate (R) 12 1/2% = 25/2% ( annual ) Number of years (n) = 3 Amount, A = p( 1 + R/100 )n = Rs [10800 (1 +...
Interest paid by Fabina = P x R x T/100 = Rs (12500 x 12 x 3/100) = Rs 4500 Amount paid by Radha at the end of 3 years = A =...
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