The class marks of distribution are : 6, 10, 14, 18, 22, 26, 30. Find the class size and the class interval.
(b) Difference = 270 - 216 = 54 According to the question, 8% of total aggregate marks = 54 Total aggregate marks = 54 x 100/8 = 675
1 Answers 1 views(e) According to the question, (40 – 4)% of x = 261 Max marks = 261/36 x 100 = 725
1 Answers 1 views(d) Total marks obtained by the student = 6 x 64/100 x 150 = 576 Marks obtained in Hindi and English = 25% of 576 = 576 x 25/100= 14
1 Answers 2 views(a) Let the maximum marks be x (265+55) = 40x/100 or 320 x 100= 40x x= 320 x 100/40 = 800
1 Answers 1 viewsHere, number of students = 4 Average = 65 sum of marks obtained = 65 × 4 = 260
1 Answers 1 viewsThe average marks of a student in seven subjects is 41. (a) New average marks = (7x41-14+42) /7 =(287+28)/7 =315/7 =45
1 Answers 1 views(a) Total marks in the test = (280 + 80) x 100 /45 = 800 Passing marks for girls = 800 x 30/100 = 240 Required marks = 240 – 108 = 132
1 Answers 1 views(e) Let the maximum marks be x According to the question, 35x /100 +42 =336 x = 840
1 Answers 1 views(d) Marks scored by Mathew = 42 + 51 + 58 + 35 +48 = 234 Max.Marks = 60 × 5 = 300 Percentage scored = 234 /300 x 100 = 78%
1 Answers 1 views(b) Marks scored in subject B = 150 × 56% = 84 Total marks scored in all the 3 subjects = (150 × 3) × 54% = 243 Marks scored in subject C...
1 Answers 1 views