150 mL of 0.5 N nitric acid solutions at 25.350C was mixed with 150 mL of 0.5 N sodium hydroxide solutions at the same temp. The final temperature was recorded to be 28.770C. Calculate the heat of neutralization of nitric acid with sodium hydroxide.


Share with your friends
Call

Total mass of solution = 150 + 150 = 300 g

Q = Total heat produced

= 300 x (28.77-25.35) cal

=300 x 3.42= 1026 cal

Heat of neutralization = Q/150 x 1000 x 1/0.5 = 13.68 Kcal

Since heat is liberated, heat of neutralization should be negative. So heat of neutralization = -13.68 Kcal

Talk Doctor Online in Bissoy App