The light emitted in the transition n = 3 to n = 2 in hydrogen is called Hα light. Find the maximum work function a metal can have so that Hα light can emit photoelectrons from it.


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n1 = 2, n2 = 3

Energy possessed by Hα light

= 13.6 (1/n12 – 1/n22) = 13.6 x (1/4 – 1/9) = 1.89 eV.

For Hα light to be able to emit photoelectrons from a metal the work function must be greater than or equal to 1.89 ev.

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