This sparingly soluble salts AB and XY2 have the same solubility product. Which salt will be more soluble? Explain.


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Suppose solubility of AB =a mol L-1 . Then AB ------> A+ + B- , Ksp= [A+ ] [B--] = a*a =a2 

Therefore a= under root Ksp 

Suppose solubility of salt XY2 = b mol L-1 . Then 

XY2------> X2+ 2 Y- ,K sp =[X2+] [Y- ] 2 = b (2b)2 i,e., 4b3 = Ksp or b= (Ksp/4) 1/3 

Obviously b>a (as Ksp have values with negative powers of 10). Hense, salt XY2 is more soluble.

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