20 mol of Chlorine gas occupies a volume of 800 mL at 300 K and 5 x 106 Pa pressure. Calculate the compressibility factor of the gas.

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20 mol of Chlorine gas occupies a volume of 800 mL at 300 K and 5 x 106 Pa pressure. Calculate the compressibility factor of the gas.

20 mol of Chlorine gas occupies a volume of 800 mL at 300 K and 5 x 10⁶ Pa pressure. Calculate the compressibility factor of the gas. Comment on the compressibility of the gas under these conditions

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Salim Ahmed Kawsar · Answer 1 · Feb 05, 2023 15:29:48

P = 5 x 10⁶

Pa = 5 x 10⁶ / 10⁵ bar

n = 20

T = 300 K

R = 0.083 L bar K^-1 mol^-1

V_real = 800 mL

V_ideal= nRT/P

Putting values , we have

Vi_deal = 1004 mL

Z = V_real/ V_ideal= 800/1004 = 0.796

As Z is less than 1, it means gas is more compressible under these conditions.

20 mol of Chlorine gas occupies a volume of 800 mL at 300 K and 5 x 106 Pa pressure. Calculate the compressibility factor of the gas.

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