Explain the diamagnetic behaviour of Hydrogen molecule on the basis of molecular orbital theory.

H22- 4e– = σ 1s2, σ∗ 1s2 B.O. = (2-2)/2 = 0 ∴ It does not exist as B.O. is zero

Geometry: Tetrahedral geometry Magnetic behaviour: Diamagnetic Ni(28)= [Ar]3d84s​​2 Unpaired electrons= 0 Therefore, complex is diamagnetic Since CO is a strong field ligand, for 4CO ligands hybridisation would be sp​3 and thus geometry will be tetrahedral.

Electron density in s-orbital is equal in all direction while it dumble shaped along one axis in p- orbitals.

When two H atoms come closer the following forces operate between them:  a. Attractive :  i.nucleus of atom and its electron  ii.nucleus of one atom and electron of other.  b.repulsive :  i.electrons of two atoms.  ii.nucleus...

(i)The bonding molecular orbital has lower energy and hence greater stability than the corresponding antibonding molecular orbital.  (ii) Just as the electron probability distribution around a nucleus in an atom is...

An atomic orbital is monocentric while a molecular orbital is polycentric.

Helium molecule (He2 ): The electronic configuration of helium atom is 1s2. Each helium atom contains 2 electrons, therefore, in He2 molecule there would be 4 electrons. These electrons will...

a) High compressibility is due to large empty space between the gas molecules.  b) Due to absence of attractive forces between the molecules, they can easily separate from one another. 

Behaviour of the marginal product in the Law of Variable Proportions: Law of variable proportions states that when total output or production of a commodity is increased by adding units...