On the basis of VSEPR theory give the geometry & bond angle of
(i) BF3 (ii) SiH4
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The bond dissociation energy of B – F in BF3 is 646kJ mol^–1 whereas that of C – F in CF4 is 515kJ mol^–1.
(c) : In BF3, B is sp2 hybridised and has a vacant 2p-orbital which overlaps laterally with a filled 2p-orbital of F forming strong pp-pp bond. However in CF4, C...
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Assertion : Bond angle of H2S is smaller than H2O. Reason : Electronegativity of the central atom increases, bond angle decreases.
(c) Bond angle of H2S (92°) < H2O (104°31). As the electronegativity of the central atom decreases, bond angle decreases. In the present case, S is less electronegative than oxygen....
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The geometry and magnetic behaviour of the complex [Ni(CO)4] are (1) square planar geometry and diamagnetic
Geometry: Tetrahedral geometry Magnetic behaviour: Diamagnetic Ni(28)= [Ar]3d84s2 Unpaired electrons= 0 Therefore, complex is diamagnetic Since CO is a strong field ligand, for 4CO ligands hybridisation would be sp3 and thus geometry will be tetrahedral.
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The geometry and magnetic behaviour of the complex [Ni(CO)4] are (1) square planar geometry and diamagnetic
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On the basis of VSEPR theory predict the shape of Hydronium (H3O+ ) ion.
pyramidal....
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Apart from tertrahedral geometry ,another possible geometry for CH4 is square planar with the four H atoms at the corners of square
In square planar geometry , the bond angle will be 90 ° which is less than bond angle in tetrahedral geometry ( 109.5 °).Therefore repulsive forces in square planar will...
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Define bond order and give the relationship between bond order and bond length
Bond order (b.o.) is defined as one half the difference between the number of electrons present in the bonding and the antibonding orbitals i.e., Bond order (b.o.) = ½ (Nb–Na) Bond...
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Apart from tetrahedral geometry another possible geometry for CH4 is square planar with four hydrogen atoms at the corners of the square
For square planar arrangement, hybridization is dsp2 which is not possible with Carbon as it does not have d orbital with it.
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Is there any change in hybridization of B and N as a result of the reaction? (L-III) BF3 + NH3 → BF3.NH3
Hybridisation of B changes from sp2 to sp3 and that of nitrogen remains same as sp3 .
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Arrange the following in order of decreasing bond angles (i) CH4, NH3, H2O, BF3, C2H2 (ii) NH3, NH2 - ,NH4 +
(i) C2H2(180) > BF3(120)>CH4 (109.28)>NH3(107) > H2O(104.5) (ii) NH4 + > NH3 >NH2 - ,
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