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Suresh can finish a piece of work by himself in 42 days. Mahesh, who is 1/5 times more efficient

Monjur Alahi

Suresh can finish a piece of work by himself in 42 days. Mahesh, who is 1/5 times more efficient as Suresh, requires X days to finish the work if working all by himself. Then what is the value of X ? 

(a) 25 days (b) 30 days (c) 35 days (d) 20 days (e) None of these


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Salim Ahmed Kawsar

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(c) Suresh, working alone for 42 days = 1 unit of work. Mahesh is 1/5 times more efficient than Suresh. So Mahesh is 6/5 times as efficient as Suresh. Hence Mahesh should require 5/6th of the time taken bySuresh.
Therefore time taken by Mahesh

=5/6× 42 = 35 days.

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