A uniform rod is kept vertically on a horizontal smooth surface at a point O. If it is rotated slightly and released, it falls down on the horizontal surface. The lower end will remain 

(a) at O 

(b) at a distance less than 1/2 from O 

(c) at a distance 1/2 from O 

(d) at a distance larger than 1/2 from O


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(c) at a distance l/2 from 0

Explanation: 

Since the rod is uniform its Center of mass (CoM) will be in the middle i.e. at l/2 distance from the ends. When the rod is vertical the CoM will bel/2 distance vertically above the point O. Since there is no force in the horizontal direction the CoM will be on the point O after it falls down. Hence the lower end will remain at a distance l/2 from O.

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