In an imaginary atmosphere, the air exerts a small force F on any particle in the direction of the particle's motion. A particle of mass m projected upward takes a time t1 in reaching the maximum height and t2 in the return journey to the original point. Then 

(a) t1, < t2 

(b) t1 > t2 

(c) t1 = t2 

(d) the relation between t1 and t2 depends on the mass of the particle.


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(b)  The original point then t1 > t2.

Explanation:

Since F is in the direction of particle's motion it will add an acceleration in the direction of motion. Let it be a. Now magnitude of upward acceleration =a-g and downward acceleration =a+g. Clearly a+g>a-g and the particle travels same distance/height. So the upward journey will take a longer time. 

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