In one average-life,
(a) half the active nuclei decay
(b) less than half the active nuclei decay
(c) more than half the active nuclei decay
(d) all the nuclei decay.
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Under what condition(s) is the magnitude of average velocity of an object equal to its average speed?
If the motion of an object is along a straight line and in the same direction, the magnitude of displacement is equal to the total path length. In that case, the...
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Under what condition(s) is the magnitude of average velocity of an object equal to its average speed?
1 Answers
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Corpus luteum in pregnancy has a long life. However, if fertilisation does not take place it remains active only for 10-12 days . Why?
This is because of a neural signal given by the maternal endometrium to its hypothalamus in presence of a zygote to sustain the gonadotropin (LH) secretion, so as to maintain...
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Pick the correct statements : (a) Average speed of a particle in a given time is never less than the magnitude of the average velocity.
(a) Average speed of a particle in a given time is never less than the magnitude of the average velocity. (b) It is possible to have a situation in which |vector dv/dt| ≠ 0 but d/dt|vector v|...
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Statement-1 : Energy is released when heavy nuclei undergo fission or light nuclei undergo fusion.
(a) : Statement-1 states that energy is released when heavy nuclei undergo fission and light nuclei undergo fusion is correct. Statement-2 is wrong The binding energy per nucleon, B/A, starts at...
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For nuclei with A > 100, (a) the binding energy of the nucleus decreases on an average as A increases
(b) the binding energy per nucleon decreases on an average as A increases (c) if the nucleus breaks into two roughly equal parts, energy is released
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The average of five numbers is 281. The average of the first two numbers is 280 and the average of the last two numbers is 178.5.
(a) Assume the third number = x According to question 2 × 280 + x + 178.5 × 2 = 281 × 5 or, 560 + x + 357 = 1405 or, x +...
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The average of 5 positive integers is 436. The average of the first two numbers is 344 and the average
(d) Third number = (436 × 5) – (344 × 2 + 554 × 2) = 2180 – 1796 = 384
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A radioactive substance has a half-life of four months. Three-fourth of the substance would decay in
(c) As it is given that half life of given substance is 4 months. The amount of substance left after 4 months = 1/2 The amount of substance left after 8 months...
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If a substance can decay by two methods and half life for two methods is T1 and T2.
λ = λ1 + λ2 ln2/T = ln2/T1 = ln2/T2 => T = (T1T2)/(T1 + T2)
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