A vessel A has volume V and a vessel B has volume 2 V. Both contain some water which has a constant volume. The pressure in the space above water is pri for vessel A and pb for vessel B.
According to Boyle’s Law P1 V1 = P2 V2
Here the temperature is constant. Therefore
1.2 X 120 = P2 X 180
OR
P2 = 1.2 X 120 /180 = 0.8 bar
Therefore, the pressure would be 0.8 bar.
The given substances in the increasing order of their densities can be represented as: Air < Exhaust from chimney < Cotton < Water < Honey < Chalk < Iron
(b) The pressure at the surface of the water will decrease.
(c) The force by the water on the bottom of the vessel will decrease.
EXPLANATION:
The option (a) is not true because...
(a) The volume of the boat immersed in water will be that volume of water which weight =50 kg. Since the density of water =1000 kg/m³, this volume will be...
The correct answer is (a) (b)
(a) The initial temperature must be equal to the final temperature.
(b) The initial internal energy must be equal to the final internal energy.
Suppose vol. of 200 mg of air at 170 C =V mL
Apply Charle’s Law V1/ T1=V2/ T2
V1/ 290 = V2/390
V2 =1.34
V1 , volume of air expelled = 1.34V1 –V1 =o.34V1...