Light falls from glass (μ= 1.5) to air. Find the angle of incidence for which the angle of deviation is 90°.

(a) Always....

As per the laws of reflection  The angle of incidence ∠i = angle of reflection ∠r  Here as given ∠i + ∠r = 90°  ∴ ∠i + ∠i = 90 °  or ∠i =...

Given,n=1.5 and the speed of light in vacuum, c = 3x 108 ms-1. We know that the refractive index is given by the expression n =c/v where c is the...

(d) : According to Brewster's law of polarization, n = taniP where ip is angle of incidence Therefore, ip = tan–1(n).

The correct answer is (b) δ

From the definition of critical angle, if refracted angle is more than 90°, then reflection occurs, which is known as total internal reflection. So, maximum angle of refraction is 90°.

(c) In the position of minimum deviation i =e=A+δM /2 =60+30/2=45o

 (c) The ratio of the sine of the angle of incidence to the sine of angle of refraction is constant. Remember that the angles of incidence (i) and refraction (r)...

Angle of incidence i = (A + δm)/2 Concept : i + e = A + δ But at minimum angle of deviation, i = e

(a) Both of the statements are correct and statement 2 is also correct explanation for statement 1. Total internal reflection is an optical phenomenon that happens when a ray of...