The average acceleration in one time period in a simple harmonic motion is

(a) : Kinetic energy is maximum at x = 0.

(c) : In vertical simple harmonic motion, maximum acceleration (aω2) and so the maximum force (maω2) will be at extreme positions. At highest position, force will be towards mean position...

(a) As x increases k increases.  Explanation: Since the motion is simple harmonic, the force F=-⍵²x where ⍵² is a constant. Equating the force applied by the student we get, -k/x=-⍵²x  →k=⍵²x²  It is...

(b) an extreme position  EXPLANATION:  At the extreme position the particle is in the same phase at consecutive appearance, hence (b) is true. In all other options, the consecutive appearance of the...

The correct answer is (d) zero. EXPLANATION:   The displacement is a vector and its magnitude is given by the line joining the initial position to the final position. Since after one time period...

The correct answer is (b) B EXPLANATION: The equation can be written as x-A=B.sin⍵t If x-A=y then y=B.sin⍵t This is the equation of a simple harmonic motion with amplitude B. Hence option(b). 

(a) 1/2 m ω2 A2   EXPLANATION:   The total energy at any instant in a simple harmonic motion is constant and equal to ½m⍵²A². Hence the average energy in one time period will also...

(a) displacement from the mean position EXPLANATION:   Since a=-⍵²x, where x is the shortest instantaneous distance from the mean position i.e. magnitude of the displacement from the mean position. Hence (a) is...

(b) an extreme position

(a) 1/2 m ω2 A2   EXPLANATION:   The total energy at any instant in a simple harmonic motion is constant and equal to ½m⍵²A². Hence the average energy in one time period will also be...