If a is an odd number, b is not divisible by 3 and LCM of a and b is P, what is the LCM of 3a and 2b?
1 Answers
Talk Doctor Online in Bissoy App
Find the LCM and HCF of the following pairs of integer and verify that LCM×HCF=Product of the two numbers.
Solution : i) 26 and 91 26=2×13×1(expressing as product of it’s prime factors) 91=7×13×1(expressing as product of it’s prime factors) So, LCM(26,91)=2×7×13×1=182 HCF(26,91)=13×1=13 Verification: LCM×HCF=13×182=2366 Product of 26 and 91 =2366 Therefore,LCM×HCF=Product of the two numbers . i) 510 and...
1 Answers 1 views
If A = {x: x is a natural number}, B ={x: x is an even natural number} C = {x: x is an odd natural number} and D = {x: x is a prime number}, find
A = {x: x is a natural number} = {1, 2, 3, 4, 5 …} B ={x: x is an even natural number} = {2, 4, 6, 8 …} C = {x:...
1 Answers 1 views
A die is thrown once. Find the probability of getting (i) a prime number; (ii) a number lying between 2 and 6; (iii) an odd number.
Answer Possible numbers of events on throwing a dice = 6 Numbers on dice = 1,2,3,4,5 and 6 (i) Prime numbers = 2, 3 and 5 Favourable number of events = 3 Probability that it...
1 Answers 1 views
If n is an odd integer, then show that n^2 – 1 is divisible by 8.
Y are you taking some odd integers as 4m+1 or 4m+3. Why no we take 2m+1 or 3m+1
1 Answers 1 views
If n is an odd integer, then show that n^2 – 1 is divisible by 8.
1 Answers
1 views
If n is an odd integer, then show that n^2 – 1 is divisible by 8.
1 Answers
1 views
If n is an odd integer, then show that n^2 – 1 is divisible by 8.
1 Answers
1 views
Prove that if x and y are both odd positive integers, then x^2 + y^2 is even but not divisible by 4.
Solution: Since x and y are odd positive integers, we have x = 2m + 1 and y = 2n + 1 => x2 + y2 = (2m + 1)2 + (2n +...
1 Answers 1 views
n^2 - 1 is divisible by 8, if n is (A) an integer (B) a natural number (C) an odd integer (D) an even integer
n2 - 1 is divisible by 8, if n is an odd integer
1 Answers 1 views
What is the probability that a number selected from the number 1 to 10 is not a prime number when each number is equally likely to be selected?
Total non-prime numbers from 1 to 10 = 6 Required probability =6/10=3/5
1 Answers 1 views