During a sale, colour pencils were being sold in packs of 24 each and crayons in packs of 32 each.

Number of color pencils in one pack = 24
No of crayons in pack = 32
∴ The least number of both colours to be purchased
= LCM of 24 and 32
= 2 × 2 × 2 × 2 × 3
= 96
∴ Number of packs of pencils to be bought = 96/24 = 4
And number of packs of crayon to be bought = 96/32= 3

So to get full packs of both colour pencils and crayons and also of same numbers in quantity, we need to find the number of packets each need to be bought. 

It’s given that, 

Number of colour pencils in a pack = 24 

Number of crayons in a pack = 32. 

So, the least number of both colour pencils and crayons need to be purchased is given by their LCM. 

L.C.M of 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 = 96 

∴ the number of packs of pencils to be bought = 96 / 24 = 4 packs 

And, the number of packs of crayon to be bought = 96 / 32 = 3 packs

For having the full packs of both and the same number of pencils and crayons, we need to find LCM of 24 and 32

Prime factors of 24 = 2 × 2 × 2 × 3

Prime factors of 32 = 2 × 2 × 2 × 2 × 2

Therefore LCM of 24 and 32 is:

2 × 2 × 2 × 2 × 2 × 3 = 96

Number of colour pencil packs = \(\frac{96}{24}\) = 4

Number of crayons packs = \(\frac{96}{32}\) = 3

Hence 4 packets of colour pencils and 3 packets of crayons would be bought.