The number of all possible matrices of order 3 x 3 with each entry 0 or 1 is:

(A) 27     (B) 18     (C) 81     (D) 512


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The correct answer is D.
The given matrix of the order 3 x 3 has 9 elements and each of these elements can be either 0 or 1. 

Now, each of the 9 elements can be filled in two possible ways. 

Therefore, by the multiplication principle, the required number of possible matrices is 29 = 512

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