In an experiment 4.5 kg of a fuel was completely burnt. The heat produced was measured to be 180,000 kJ. Calculate the calorific value of the fuel.

Answer: The balanced reaction of combustion of carbon can be written as:       C +  O2 ----------------> CO2      1       1                          1  (i) As per the balanced equation, 1 mole of carbon burns in 1 mole...

Hydrogen can be considered a cleaner fuel because its burning produces water vapour which is non-polluting. However, due to explosive nature of hydrogen, its storage and transportation is difficult

                            Carbon + Oxygen → Carbon dioxide  3g of carbon reacts with 8 g of oxygen to produce...

The calorific value of a fuel is expressed in kilojoules per kilogram (kJ/kg).

The combustion equation of naphthalene is C10H8(s)+12O2(g)→10CO2(g)+4H2O(l);ΔE=−5133kJ Δn=10−12=−2mol Now, applying the relation, ΔH=ΔE+(Δn)RT =−51335128.04kJ103J+(−2mol)(8.314J/molK)(298K) =−5133000J–4955.14J=−5137955.14J Ans : (d)

(d) : It does not violate first law of thermodynamics but violates second law of thermodynamics.

(b) : Direct conversion of chemical energy to electric energy can be made considerably more efficient (i.e. upto 75%) than the 40% maximum now obtainable through burning of fuel and...

(c) x + y = 18 (x + y)2 = 182 = 324 x2 + y2 + 2xy = 324 x2 + y2 = 324 – 2xy x2 + y2 = 324 – 2(72) x2...

(a) Rate of the equivalent capitals of Amar and Prakash for 1 month = 45000 × 12 : 30000 × 6 = 540000 : 180000 = 3 : 1 Ratio of profit sharing =...

In the past 10 years use of electricity and LPG has increased while use of wood, upla, coal, etc. has decreased.