The velocity of a body moving in a straight line is increased by applying a constant force F, for some distance in the direction of the motion. Prove that the increase in the kinetic energy of the body is equal to the work done by the force on the body.
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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
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When a force retards the motion of a body, what is the nature of work done by the force? State reason. List two examples of such a situation
The work done by the force is negative because this force acts opposite to the direction of movement of the body, thereby hindering the motion. Example: 1. Work done by the force...
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A motorcar of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km/h.
Mass of the motor car, m = 1200 kg Initial velocity of the motor car, u = 90 km/h = 25 m/s Final velocity of the motor car, v = 18 km/h...
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Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running – Oscillatory motion. (ii) Motion of a horse pulling a cart on a straight road – Straight line motion. (iii) Motion of a child in...
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A person travelling on a straight line moves with a uniform velocity v_1 for some time and with uniform velocity v_2 for the next equal time.
(a) v = (v1 + v2)/2. Explanation: Let t be the time related to each velocity. Total distance travelled =v1t+v2t. Total time taken=2t. Hence average velocity = v1t+v2t/2t =(v1+v2)/2.
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A person traveling on a straight line moves with a uniform velocity v_1 for a distance x and with a uniform velocity
(c) 2/v = 1/v1 + 1/v2. Explanation: Time taken during first phase = x/v1 and during second phase = x/v2. Total distance =2x Total time taken = (x/v1)+(x/v2) = x(1/v1 +1/v2) Average velocity =Total distance/Total time taken ...
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A person travelling on a straight line moves with a uniform velocity v1 for a distance x and with a uniform velocity v2 for the next equal distance.
(c) 2/v = 1/v1 + 1/v2. Explanation: Time taken during first phase = x/v1 and during second phase = x/v2. Total distance =2x Total time taken = (x/v1)+(x/v2) = x(1/v1 +1/v2) Average velocity =Total distance/Total...
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What is the direction of the force acting on a charge particle q, moving with a velocity vector v in a uniform magnetic field vector B?
Force, vector Fm = q vector v x vector B Obviously, the force on charged particle is perpendicular to both velocity vector v and magnetic field vector B?
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