The gravitational force between two objects is F. If masses of both objects are halved without changing distance between them, then the gravitational force would become
(a) F/4
(b) F/2
(c) F
(d) 2 F
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The force on 4 kg mass is 20 N, & that on 2kg mass is 2 N in the opp. direction. u=0.5 between these two masses. Find the frictional force
There is no friction between 4 kg mass and ground.
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The force on 4 kg mass is 20 N, & that on 2kg mass is 2 N in the opp. direction. u=0.5 between these two masses. Find the frictional force
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How does the force of gravitation between two objects change when the distance between them is reduced to half?
According to the universal law of gravitation, gravitational force (F) acting between two objects is inversely proportional to the square of the distance (r) between them, i.e., f ∝ 1 /...
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Gravitational force acts on all objects in proportion to their masses
All objects fall on ground with constant acceleration, called acceleration due to gravity (in the absence of air resistances). It is constant and does not depend upon the mass of...
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Gravitational force on the surface of the moon is only 1/6 as strong as gravitational force on the Eart
Weight of an object on the moon = 1 / 6 × Weight of an object on the Earth Also, Weight = Mass × Acceleration Acceleration due to gravity, g = 9.8 m/s2 Therefore,...
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How does the force of attraction between the two bodies depend upon their masses and distance between them?
F ∝ m1m2 and F ∝ 1/d2 This hypothesis is not correct. The two bricks, like a single body, fall with the same speed to reach the ground at the same time...
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What will cause greater change in kinetic energy of a body? Changing its mass or changing its velocity.
As K .E = 1/2 mv2 therefore, K . E ∝ m K . E ∝ v2 Therefore, the change in velocity of a body will cause greater change in kinetic energy.
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A truck of mass M is moved under a force F. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved
Calculate using F= m a Acceleration becomes one-fourth of the original.
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Let V and E be the gravitational potential and gravitational field at a distance r from the centre of a uniform spherical shell.
(c) B is correct but A is wrong. EXPLANATION: (A) is not correct because the gravitational potential inside the shell is constant =-GM/a, where a is the radius of the shell. As...
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Let V and E be the gravitational potential and gravitational field at a distance r from the centre of a uniform spherical shell,
(c) B is correct but A is wrong. EXPLANATION: (A) is not correct because the gravitational potential inside the shell is constant =-GM/a, where a is the radius of the shell. As...
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