The increasing order of reactivity among group 1 elements is Li < Na < K < Rb
It is given that: n(S) = 21, n(T) = 32, n(S ∩ T) = 11 We know that: n (S ∪ T) = n (S) + n (T) – n (S...
1 Answers 1 viewsIt is given that: n(X) = 40, n(X ∪ Y) = 60, n(X ∩ Y) = 10 We know that: n(X ∪ Y) = n(X) + n(Y) – n(X ∩ Y) ∴ 60 = 40...
1 Answers 1 viewsThe elements present in group 1 have only 1 valence electron, which they tend to lose. Group 17 elements, on the other hand, need only one electron to attain the...
1 Answers 3 viewsThe oxidizing character of elements increases from left to right across a period. Thus, we get the decreasing order of oxidizing property as F > O > N. Again, the...
1 Answers 1 views[Hint : p-p multiple bonds are formed by N due to its small size.]
1 Answers 1 views[Hint : CH3F < CH3Cl < CH3Br < CH3I]
1 Answers 1 viewsC2H5COCH3 < CH3COCH3 < CH3CHO < HCHO
1 Answers 1 views(a) Na or K (b) Ca (c) Hg Reactivity order: Hg < Ca < Na < K
1 Answers 1 views(i) The arrangement of metals in the vertical column in the order of decreasing reactivity is called reactivity series or activity series. A metal placed above hydrogen in the activity...
1 Answers 1 views(c) For nitrogen oxidation states from +1 to +4 disproportionate in acidic solution only. Oxidation state of phosphorous in P2O5 is + 5 whereas in P2O5 is +3 thus P2O5...
1 Answers 1 views