Here, in case of concave mirror
u=10 cm [u, is always negative]
v =?;m = - 3 [real image]
Now the magnification formula is
m= -v/u or -3= -(v/-10)
or , v = -30 cm.
Image will...
Given, u=-10 cm, f=+15 cm,v=?
From mirror formula, 1/f=1/v+1/u
or 1/v=1/f=1/u
=1/v=1/15=1/(-10)=1/15+1/10=(2+3)/30
or v=30/5=+6 cm
That is image is formed at a distance of 6 cm from the mirror behind it. The image is erect...
Radius of curvature of convex mirror, R = 30 cm.
Focal length of convex mirror, f=R/2=30cm/2=15cm
Now h=5cm,u=-20cm,v=?,h'=?
Using the mirror formula 1/f=1/u+1/v, we have
1/v=1/f=1/u=1/15=1/-20=1/15+1/20=(4+3)/60
v=60/7=8.6cm.
Thus, image is formed at a distance of 8.6cm...
(i) The incident ray, the normal to the mirror at the point of incidence and the reflected ray, all lie in the same plane, and
(ii) The angle of incidence is...
(d) 15 cm behind the mirror.
EXPLANATION:
The option can be selected by suitable reasoning. In a convex mirror, the object at infinity has its image at the focus behind the mirror....