An Internet Service Provider (ISP) has the following chunk of CIDR-based IP addresses available with it: 245.248.128.0/20. The ISP wants to give half of this chunk of addresses to Organization A, and a quarter to Organization B, while retaining the remaining with itself. Which of the following is a valid allocation of addresses to A and B?

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  1. 245.248.136.0/21 and 245.248.128.0/22
  2. 245.248.128.0/21 and 245.248.128.0/22
  3. 245.248.132.0/22 and 245.248.132.0/21
  4. 245.248.136.0/24 and 245.248.132.0/21

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Option 1 : 245.248.136.0/21 and 245.248.128.0/22

The correct answer is Option 1.

 [ alt="cnISPproblem" src="//storage.googleapis.com/tb-img/production/21/07/cnISPproblem.png" style="width: 385px; height: 265px;">

Since Half of 4096 post addresses must be given organization A, we can set the 12th bit to 1, include that bit into the network path of organization A. So the valid allocation of address to A is 245.248.136.0/21.

The 12th bit is set to 0, but we need only half of the 2048 address, 13th bit can be set to be 0 addresses to B is 245.248.128.0/22.

Hence the correct answer is 245.248.136.0/21 and 245.248.128.0/22.

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AhmedNazir

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Option 1 : 245.248.136.0/21 and 245.248.128.0/22

Four different ways are:

(i)  245.248.128.0/21 and 245.248.136.0/22

(ii) 245.248.128.0/21 and 245.248.140.0/22

(iii) 245.248.136.0/21 and 245.248.128.0/22

(iv) 245.248.136.0/21 and 245.248.140.0/22

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