A solid iron pole consists of a cylinder of height 110 cm and base diameter 12 cm, which is surmounted by another cylinder of height 30 cm and radius 4 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. (Use π = 3.14)?

LohaHridoy
  1. 111.53 kg
  2. 111572.8 gram
  3. 111532.39 kg
  4. 1111.59 gram

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AhmedNazir

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Option 1 : 111.53 kg

Formula Used:

The volume of the cylinder = πR2 h

Where r = radius of the cylinder, h = height of the cylinder.

Mass = Density × volume

Given: 

The height of the big cylinder (H) = 110 cm

Radius of the base (R) = 12/2 = 6 cm

The height of the small cylinder (h) = 30 cm

Radius of the base (r) = 4 cm

Density of steel = 8g/cm3

Calculation:

So, the volume of the big cylinder = πR2H

= π(6)2 × 110 cm3

= 12434.4 cm3

And, the volume of the smaller cylinder = πr2h

= π(4)2 × 30 cm3

= 1507.2 cm3

∴ Volume of iron = Volume of the big cylinder + Volume of the small cylinder

= 12434.4 + 1507.2

= 13941.6 cm3

We know that,

Mass = Density × volume

So, mass of the pole = 8 × 13941.6 cm3

= 111532.8 gram = 111.53 Kg 

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