1 Answers
Call
Option 1 : 12
12 Type-1 workers completed = 10 days
1 Type-1 worker will complete = 12 × 10 = 120 days
Since Type-1 worker 2.5 times efficient than type2
1 type-2 worker complete = 2.5 × 120 = 300 days
Work done by Type-1 worker in 1 day = 1/120
Work done by 4 Type-1worker in 1 day = 4 × (1/120) = 1/30
Work done by Type-2 worker in 1 day = 1/300
Work done by 15 Type-2 worker in 1 day = 15 × (1/300) = 1/20
Work done by (4 Type-1 + 15 Type-2) worker in 1 day = 1/30 + 1/20 = 5/60 = 1/12
⇒ Together 4 Type-1 and 15 Type-2 worker can complete the whole work in 12 days.
0
like
0 dislike
Talk Doctor Online in Bissoy App
Adil and Biren together can complete a task in 20 days. Biren and Chirag together can complete the same task in 50 days. Adil and Chirag together can complete the same task in 40 days. If the same task was to be done by them alone, what would be the ratio of time taken by Adil alone to Biren alone
A. 11: 9
B. 11 : 3
C. 7 : 9
D. 9 : 11?
Option 1 : DGiven: Adil and Biren together can complete a task in = 20 days Bire and Chirag together can complete the same task in = 50 days Adil and Chirag together...
1 Answers 1 views
Raj alone can complete the work in 20 days and Radha alone can complete the work in M days while Ram alone can complete the work in 24 days. Raj and Radha can complete half of the work in 6 days. Radha works for 18 days then Raj and Ram join her to complete the remaining work. In what time total work gets completed?
Option 4 : 21.2 daysGiven: Raj's 1 day's work = 1/20 Radha's 1 day's work = 1/M Ram's 1 day’s work = 1/24 Calculation: According to the question, (1/20 + 1/M) = 1/12 ⇒ 1/M = 1/12...
1 Answers 5 views
In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option.
Quantity I: A alone can complete the work in 45 days while B alone can complete the work in 30 days. If both work for 10 days then A left the job and remaining work is completed by B and C in 16/3 days. In what time A and C can complete the work
Quantity II: 26/3 days ?
Option 4 : Quantity I > Quantity IIQuantity I: A's 1 day's work = 1/45 B's 1 day's work = 1/30 (A + B)’s 1 days work = 1/45 + 1/30 = 1/18 (A...
1 Answers 1 views
Newton, Einstein, and Tesla working alone can do a piece of work in 20, 30, and 60 days respectively. All three of them start the work together, but after x days Newton leaves and then after y more days Einstein leaves and Tesla completes the remaining work. If Einstein had not left, Tesla and Einstein would have completed the remaining work in (y + 6) days after Newton had left. If both Newton and Einstein had stayed, the work would have been completed in (x + 6) days. What is the total number of days taken to complete the work?
Option 3 : 28Given: Newton’s Time = 20 days Einstein’s Time = 30 days Tesla’s Time = 60 days All three together time = (x + 6) days Calculation: The data provides three different combinations of...
1 Answers 1 views
Adil and Biren together can complete a task in 20 days. Biren and Chirag together can complete the same task in 50 days. Adil and Chirag together can complete the same task in 40 days. If the same task was to be done by them alone, what would be the ratio of time taken by Adil alone to taken by Biren
A. 11 : 9
B. 11 : 3
C. 7 : 9
D. 9 : 11?
Option 1 : DLet, Adil’s efficiency = x/day Biren’s efficiency = y/day Chirag’s efficiency = z/day According to the question, ⇒ x + y = 1/20 … (1) According to the question, ⇒ y...
1 Answers 2 views
A and B together can complete a work in 15 days, while B alone can complete the same work in 40 days. If the efficiency of C is 20% more than that of A and the time taken by C and D together to complete a work is 80% of that taken by A and B together, then at what time D alone can complete the work?
Option 2 : 30 daysGiven that, (1/A) + (1/B) = 1/15 And, (1/B) = 1/40 So, (1/A) = (1/15) – (1/40) = 5/120 = 1/24 Time is taken by A alone to complete the...
1 Answers 1 views
P can complete ¼ of some work in 10 days, Q can complete 40% of the same work in 48 days. R completes 1/8 of the work in 5 days and S does 1/10 of the work in 2 days. ½ of total work is done by (Q + R) and remaining work is done by (P + S). What will be the ratio of the days for completing ½ of work by (Q + R) and remaining work by the (P + S)?
Option 3 : 27 ∶ 12P completes full work = 10 × 4 = 40 Q completes full work = 48 × 100/40 = 120 R completes full work = 8 ×...
1 Answers 1 views
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.
Quantity A: M can finish a work in 12 days and N can do same work in 15 days. M and N worked for 5 days then M left the job. What fraction of work remains after M left the job
Quantity B: A is 25% more efficient than B. If A can complete the work in 16 days and B work alone for first three days then what fraction of work remains?
Option 2 : Quantity A < Quantity BQuantity A: Given, M’s 1 day’s Work = 1/12 N's 1 day’s work = 1/15 Then, (M + N)’s 1 day’s work = (1/12) + (1/15) = 27/(15 ×...
1 Answers 1 views
Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.
Quantity A : 10 men and 15 women can complete a piece of work in 15 days while 5men and 10 women can complete the work in 25 days. What part of work a woman can complete in 1 day
Quantity B : 5 women and 10 girls can complete stitching work in 10 days and 7 women and 5 girls can complete this same work in 15 days. What fraction of work remains if 6 girls work alone for 6 days?
Option 2 : Quantity A < Quantity BQuantity A: Let 1 men’s 1 day’s work = x and 1 women’s 1 day’s work = y Then, 10x + 15y = 1/15 5x + 10y...
1 Answers 1 views
Given below are two quantities named 1 and 2. Based on the given information, you have to determine the relationship between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answers.
Quantity 1: P and Q can do a work in 6 days and Q and R can do a work in 60/7 days and P and R can do a work in 20/3 days. If Q and R work for first 2 days and left the work. Find the total time taken by P to complete the remaining work.
Quantity 2: A and B can do a work in 8/3 days, B and C can do the same work in 3 days and A and C can do the same work in 24/5 days. In what time C alone can complete the work?
Option 2 : Quantity 1 < Quantity 2Quantity 1: Given, P and Q together can complete the work in = 6 days Q and R together can complete the work in = 60/7...
1 Answers 1 views