For a reversible adiabatic process the entropy change is zero since $$dS = \frac{{\delta Q}}{T}$$
But the enthalpy change need not be zero since the internal energy and pressure energy may vary during the process.
Answer: Option 1
The sensible heat factor during cooling and dehumidification process is given by (hA - h2)/ (h1 - h2)
where,
h₁ = Enthalpy of air entering the cooling...