- There is a NullPointerException. Everything went fine.
- There is a NullPointerException.
- There is a NullPointerException. There is an Exception.
- This code will not compile, because in Java there are no pointers.
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what is the result of the following piece of code: public class Person{ public void talk(){ System.out.print("I am a Person"); } } public class Student extends Person{ public void talk(){ System.out.print("I am a Student"); } } public class Test{ public static void main(String args[]){ Person p = new Student(); p.talk(); } }?
Answer: Option 2 Let'
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What is the result of compiling and running the following code class Base{ public Base(){ System.out.print("Base"); } } public class Derived extends Base{ public Derived(){ this("Examveda"); System.out.print("Derived"); } public Derived(String s){ System.out.print(s); } public static void main(String[] args){ new Derived(); } }?
Answer: Option 3 1. new Derived(); statement executes and invoke the non-parametrized constructor of derived class i.e. public Derived(); 2. As Derived class is a subclass of class Base so super(); executes...
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What is the output for the below code import java.io.FileNotFoundException; class A{ public void printName() throws FileNotFoundException{ System.out.println("Value-A"); } } class B extends A{ public void printName() throws NullPointerException{ System.out.println("Name-B"); } } public class Test{ public static void main (String[] args) throws Exception{ A a = new B(); a.printName(); } }?
Answer: Option 3 The overriding method can throw any unchecked (runtime) exception, regardless of exception thrown by overridden method. NullPointerException is RuntimeException so compiler will not complain.
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What will be the output when the following program is compiled and executed abstract class TestAbstract{ String my_name; String myName(){ my_name = "Examveda"; return my_name; } abstract void display(); } public class Test extends TestAbstract{ void display(){ String n = myName(); System.out.print("My name is "+ n); } public static void main(String args[]){ Test t = new Test(); t.display(); } }?
Answer: Option 1 The options B, C and D are incorrect options as in Java we can declare an abstract class comprising of abstract and non-abstract methods that will not...
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What will be the output class A{ static void method(){ System.out.println("Class A method"); } } class B extends A{ static void method(){ System.out.println("Class B method"); } } public class Test{ public static void main(String args[]){ A a = new B(); a.method(); } }?
Answer: Option 1 Overriding in Java simply means that the particular method would be called based on the run time type of the object and not on the compile time...
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What will be the output interface A{ public void method(); } class One{ public void method(){ System.out.println("Class One method"); } } class Two extends One implements A{ public void method(){ System.out.println("Class Two method"); } } public class Test extends Two{ public static void main(String[] args){ A a = new Two(); a.method(); } }?
Answer: Option 2 Let'
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What will be the output class MyClass{ public String test(){ try{ System.out.print("One"); return ""; } finally{ System.out.print("Two"); } } } public class Test{ public static void main(String args[]){ MyClass m = new MyClass(); m.test(); } }?
Answer: Option 3 Finally block will execute irrespective of return statement in try block.
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What will be the output after compiling and executing the following code public class Test implements Runnable{ public static void main(String[] args) throws InterruptedException{ Thread a = new Thread(new Test()); a.start(); System.out.print("Begin"); a.join(); System.out.print("End"); } public void run(){ System.out.print("Run"); } }?
Answer: Option 3 Let'
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