1. 9
  2. 30
  3. 36
  4. 15

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Answer: Option 4

There are 6 candidates and a voter has to vote for any two of them. So, the required number of ways is, $$\eqalign{ & { = ^6}{{\text{C}}_2} \cr & = \frac{{6!}}{{2! \times 4!}} \cr & = 15 \cr} $$

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