What is the result of compiling and running the following code class Base{ private Base(){ System.out.print("Base"); } } public class test extends Base{ public test(){ System.out.print("Derived"); } public static void main(String[] args){ new test(); } }?

LohaHridoy
  1. BaseDerived
  2. Derived
  3. Exception is thrown at runtime
  4. Compilation Error

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AhmedNazir

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Answer: Option 4

Implicit super constructor Base is not visible, must explicitly invoke another constructor.

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what is the result of the following piece of code: public class Person{ public void talk(){ System.out.print("I am a Person"); } } public class Student extends Person{ public void talk(){ System.out.print("I am a Student"); } } public class Test{ public static void main(String args[]){ Person p = new Student(); p.talk(); } }?

Answer: Option 2 Let'

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Answer: Option 1 Let'

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Answer: Option 1 The options B, C and D are incorrect options as in Java we can declare an abstract class comprising of abstract and non-abstract methods that will not...

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Answer: Option 1 Overriding in Java simply means that the particular method would be called based on the run time type of the object and not on the compile time...

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Answer: Option 2 Let'

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Answer: Option 2 Let'

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Answer: Option 4 Let'

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Answer: Option 3 Let'

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Answer: Option 3 Let'

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