Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son ?

Question

Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son ?

12 years
13 years
14 years
15 years

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AhmedNazir · Answer 1 · Sep 01, 2022 13:21:41

Answer: Option 3

Let son's age 10 years ago be x years. Then, man's age 10 years ago = 7x years Son's present age = (x + 10) years, Man's present age = (7x + 10) years $$\eqalign{ & \therefore {\text{2}}\left[ {\left( {7x + 10} \right) + 2} \right]{\text{ = 5}}\left[ {\left( {x + 10} \right) + 2} \right] \cr & \Rightarrow 2\left( {7x + 12} \right) = 5\left( {x + 12} \right) \cr & \Rightarrow 14x + 24 = 5x + 60 \cr & \Rightarrow 9x = 36 \cr & \Rightarrow x = 4 \cr} $$ Son's present age = (x + 10) years = (4 + 10) years = 14 years

Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son ?

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