A candidate scoring 25% marks in an examination fails by 30 marks while another candidate who score 50% marks gets 20 marks more than the minimum pass marks. what is the minimum pass mark?

Let the maximum marks be 'x'. Then, according to the question. (25 % of x) + 30 = (50 % of x) - 20 ⇒ x/4 + 30 = x/2 - 20 ⇒ (x/4) - (x/2) = - 20 - 30 ⇒ (x - 2x)/4 = - 50 ⇒ - x/4 = - 50 ⇒ - x = - 200 ⇒ x = 200 So, the maximum marks are 200. Minimum passing marks are = x/4 + 30 = 200/4 + 30 = 50 + 30 = 80 marks Minimum passing marks are 80