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A box has 8 red balls and 8 green balls. Two balls are drawn randomly in succession from the box without replacement. The probability that the first ball drawn is red and the second ball drawn is green is
A
$$\frac{4}{{15}}$$
B
$$\frac{7}{{16}}$$
C
$$\frac{1}{2}$$
D
$$\frac{8}{{15}}$$
Correct Answer:
$$\frac{4}{{15}}$$
Directions: Seven different boxes A, B, C, D, E, F and G of different colours viz., Orange, Pink, Purple, Yellow, Blue, Red and Green are arranged one above the other. The box at the bottom of arrangement is numbered 1, the above box is numbered 2 and so on. B is immediately above E. More than two boxes are above the Orange box. The Yellow box is immediately below A. Only one box is between the Orange box and F. G is immediately above the Red box. Only one box is between B and the Pink box. Only two boxes are between the Pink and the Green box. Only two boxes are between the Yellow box and the Orange box. The Purple box is neither at the top nor at the bottom of the arrangement.B is above Pink box. C is immediately above F. Neither C nor G is a Yellow box. G is not a Orange box. Question: Which combination represents the position of C and its colour?
A
6-Green
B
6-Red
C
5-Purple
D
7-Blue
In a bag which contains 40 balls, there are 18 red balls and some green and blue balls. If two balls are picked up from the bag without replacement, then the probability of the first ball being red and second being green is 3/26. Find the number of blue balls in the bag.
A
16
B
12
C
10
D
14
A box contains 4 white balls and 3 red balls. In succession, two balls are randomly selected and removed from the box. Give that the first removed ball is white, the probability that the second removed ball is red is
A
$$\frac{1}{3}$$
B
$$\frac{3}{7}$$
C
$$\frac{1}{2}$$
D
$$\frac{4}{7}$$
A box contains 4 red balls and 6 black balls. Three balls are selected randomly from the box one after another, without replacement. The probability that the selected set contains one red ball and two black balls is
A
$$\frac{1}{{20}}$$
B
$$\frac{1}{{12}}$$
C
$$\frac{3}{{10}}$$
D
$$\frac{1}{2}$$
Four red balls, four green balls and four blue balls are put in a box. Three balls are pulled our of the box at random one after another without replacement. The probability that all the three balls are red is
A
$$\frac{1}{{72}}$$
B
$$\frac{1}{{55}}$$
C
$$\frac{1}{{36}}$$
D
$$\frac{1}{{27}}$$
A box contains 5 white balls and 3 red balls. Two balls are withdrawn from the box randomly, one after another (without replacement). The probability that the two balls withdrawn are of different colour is
A
$$\frac{{15}}{{64}}$$
B
$$\frac{{25}}{{64}}$$
C
$$\frac{{25}}{{56}}$$
D
$$\frac{{30}}{{56}}$$
There are 87 balls in a jar. Each ball is painted with at least one of two colors, red or green. It is observed that 2/7 of the balls that have red color also have green color, while 3/7 of the balls that have green color also have red color. what fraction of the balls in the jar has both red and green colors?
A
6/14
B
2/7
C
6/35
D
6/29
A bag contains 4 red balls, 6 blue balls and 8 pink balls. One ball is drawn at random and replaced with 3 pink balls. A probability that the first ball drawn was either red or blue in colour and the second drawn was pink in colour ?
A
$$\frac{12}{21}$$
B
$$\frac{13}{17}$$
C
$$\frac{11}{30}$$
D
$$\frac{13}{18}$$
E
None of these
Two bags A and B have equal number of bails. Bag A has 20% red balls and 80% green bails. Bag B has 30% red bails. 60% green balls and 10% yellow balls. Contents of Bags A and B are mixed thoroughly and a ball is randomly picked from the mixture. What is the chance that the ball picked is red?
A
20%
B
25%
C
30%
D
40%
A box contains 5 black and 5 red balls. Two balls are randomly picked one after another from the box, without replacement. The probability for both balls being red is
A
$$\frac{1}{{90}}$$
B
$$\frac{1}{2}$$
C
$$\frac{{19}}{{90}}$$
D
$$\frac{2}{9}$$