A and B are two alloys of gold and copper prepared by mixing metals in the ratio 5 : 3 and 5 : 11 respectively. Equal quantities of these alloys are melted to form a third alloys C. The ratio of gold and copper in the alloy C is -
Correct Answer: 15 : 17
According to the question,
\\] Equal quantity are mixed
$$\eqalign{ & {\text{Alloy A }} \to 10\,\,\,:\,\,\,6\,\,\,\, = 16 \cr & {\text{Alloy B }} \to {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,5\,\,\,\,\,:\,\,\,11\, = 16 \cr & {\text{Alloy C }} \to {\bf{15}}\,\,\,:\,\,{\bf{17}} \cr} $$
\\] Equal quantity are mixed
$$\eqalign{ & {\text{Alloy A }} \to 10\,\,\,:\,\,\,6\,\,\,\, = 16 \cr & {\text{Alloy B }} \to {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,5\,\,\,\,\,:\,\,\,11\, = 16 \cr & {\text{Alloy C }} \to {\bf{15}}\,\,\,:\,\,{\bf{17}} \cr} $$