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A and B are two alloys in which ratios of gold and copper are 5 : 3 and 5 : 11 respectively. If these equally amount of two alloys are melted and made alloy C. What will be the ratio of gold and copper in alloy C?

Correct Answer: 15 : 17
Ratio of Gold and Copper in Alloy A = 5 : 3Ratio of Gold and Copper in Alloy B = 5 : 11Amount of Gold in Alloy A = $$\frac{5}{8}$$Amount of Gold In Alloy B = $$\frac{5}{{16}}$$Amount of Copper in A = $$\frac{3}{8}$$Amount of Copper in B = $$\frac{{11}}{{16}}$$Amount of Gold In C, = (Amount of gold in A + Amount of gold in B) = $$\frac{5}{8}$$ + $$\frac{5}{{16}}$$ = $$\frac{{10 + 5}}{{16}}$$ = $$\frac{{15}}{{16}}$$Amount of Copper in C, = Amount of Copper in A + Amount of Copper in B = $$\frac{3}{8}$$ + $$\frac{{11}}{{16}}$$ = $$\frac{{17}}{{16}}$$So,Ratio of Gold and Copper in C,$$ = \frac{{15}}{{16}}:\frac{{17}}{{16}} = 15:17$$

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