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Find branch current IR2.<br> <img src="/images/question-image/electrical-engineering/branch,-loop-and-node-analyses/1526014758-1.png" title="Branch, Loop and Node Analyses mcq question image" alt="Branch, Loop and Node Analyses mcq question image">
A
5.4 mA
B
-5.4 mA
C
113.0 mA
D
119.6 mA
Correct Answer:
113.0 mA
Using the mesh current method, find the branch current, IR1, in the above figure.
A
115 mA
B
12.5 mA
C
12.5 A
D
135 mA
Find the node voltage VA.
A
518 mV
B
5.18 V
C
9.56 V
D
956 mV
Find the node voltage VA.
A
6 V
B
12 V
C
4.25 V
D
3 V
What is the current through R2?
A
3.19 A
B
319 mA
C
1.73 A
D
173 mA
What is the voltage drop across R1?
A
850 mV
B
7.82 V
C
9.18 V
D
918 mV
Consider a conducting loop of radius a and total loop resistance R placed in a region with a magnetic field B thereby enclosing a flux $${\phi _0}$$ . The loop is connected to an electronic circuit as shown, the capacitor being initially uncharged.
If the loop is pulled out of the region of the magnetic field at a constant speed u, the final output voltage V
out
is independent of
A
$${\phi _0}$$
B
u
C
R
D
C
An infinitely long wire carrying a current $$I\left( t \right) = {I_0}\cos \left( {\omega t} \right)$$ is placed at a distance a from a square loop of side a as shown in the figure. If the resistance of the loop is R, then the amplitude of the induced current in the loop is
A
$$\frac{{{\mu _0}}}{{2\pi }} \cdot \frac{{a{I_0}\omega }}{R}\ln 2$$
B
$$\frac{{{\mu _0}}}{\pi } \cdot \frac{{a{I_0}\omega }}{R}\ln 2$$
C
$$\frac{{2{\mu _0}}}{\pi } \cdot \frac{{a{I_0}\omega }}{R}\ln 2$$
D
$$\frac{{{\mu _0}}}{{2\pi }} \cdot \frac{{a{I_0}\omega }}{R}$$
Branch current and loop current relation is expressed in matrix form shown below, where Ij represents branch current and Ik represents loop current. = The rank of the incidence matrix is?
A
= The rank of the incidence matrix is? ] 4
B
I1; I2; I3; I4; I5; I6; I7; I8
C
I1; I2; I3; I4; I5; I6; I7; I8
D
I1; I2; I3; I4; I5; I6; I7; I8
“In any linear bilateral network, if a source of e.m.f. E in any branch produces a current I in any other branch, then same e.m.f. acting in the second branch would produce the same current / in the first branch”. The above statement is associated with
A
Compensation theorem
B
Superposition theorem
C
Reciprocity theorem
D
None of the above
Let $${I_1}$$ and $${I_2}$$ represents mesh currents in the loop abcda and befcb respectively. The correct expression describing Kirchhoff's voltage loop law in one of the following loops is,
A
$$30{I_1} - 15{I_2} = 10$$
B
$$ - 15{I_1} + 20{I_2} = - 20$$
C
$$30{I_1} - 15{I_2} = - 10$$
D
$$ - 15{I_1} + 20{I_2} = 20$$